4112121283 has 2 divisors, whose sum is σ = 4112121284. Its totient is φ = 4112121282.

The previous prime is 4112121253. The next prime is 4112121319. The reversal of 4112121283 is 3821212114.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4112121283 is a prime.

It is a super-2 number, since 2×4112121283² = 33819082892203132178, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4112121253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056060641 + 2056060642.

It is an arithmetic number, because the mean of its divisors is an integer number (2056060642).

Almost surely, 2^4112121283 is an apocalyptic number.

4112121283 is a deficient number, since it is larger than the sum of its proper divisors (1).

4112121283 is an equidigital number, since it uses as much as digits as its factorization.

4112121283 is an evil number, because the sum of its binary digits is even.

The product of its digits is 768, while the sum is 25.

The square root of 4112121283 is about 64125.8238387625. The cubic root of 4112121283 is about 1602.0963774420.

Adding to 4112121283 its reverse (3821212114), we get a palindrome (7933333397).

The spelling of 4112121283 in words is "four billion, one hundred twelve million, one hundred twenty-one thousand, two hundred eighty-three".