Base | Representation |
---|---|
bin | 100110010011000000… |
… | …111110101001100111 |
3 | 10221010210211001122001 |
4 | 212103000332221213 |
5 | 1133204012304111 |
6 | 30520230150131 |
7 | 2654010354313 |
oct | 462300765147 |
9 | 127123731561 |
10 | 41121213031 |
11 | 16491941a88 |
12 | 7b774b2347 |
13 | 3b5444c822 |
14 | 1dc146cb43 |
15 | 110a15d1c1 |
hex | 99303ea67 |
41121213031 has 2 divisors, whose sum is σ = 41121213032. Its totient is φ = 41121213030.
The previous prime is 41121213017. The next prime is 41121213043. The reversal of 41121213031 is 13031212114.
41121213031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 41121213031 - 25 = 41121212999 is a prime.
It is a super-2 number, since 2×411212130312 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41121213061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20560606515 + 20560606516.
It is an arithmetic number, because the mean of its divisors is an integer number (20560606516).
Almost surely, 241121213031 is an apocalyptic number.
41121213031 is a deficient number, since it is larger than the sum of its proper divisors (1).
41121213031 is an equidigital number, since it uses as much as digits as its factorization.
41121213031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 41121213031 its reverse (13031212114), we get a palindrome (54152425145).
The spelling of 41121213031 in words is "forty-one billion, one hundred twenty-one million, two hundred thirteen thousand, thirty-one".
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