Base | Representation |
---|---|
bin | 100110010011000001… |
… | …010011111111010000 |
3 | 10221010210222111112010 |
4 | 212103001103333100 |
5 | 1133204023103212 |
6 | 30520232102520 |
7 | 2654011200162 |
oct | 462301237720 |
9 | 127123874463 |
10 | 41121300432 |
11 | 164919a1713 |
12 | 7b77534a40 |
13 | 3b54480544 |
14 | 1dc1492932 |
15 | 110a17903c |
hex | 993053fd0 |
41121300432 has 40 divisors (see below), whose sum is σ = 106248824640. Its totient is φ = 13704674560.
The previous prime is 41121300413. The next prime is 41121300503. The reversal of 41121300432 is 23400312114.
It is a super-2 number, since 2×411213004322 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 41121300399 and 41121300408.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 209332 + ... + 355052.
It is an arithmetic number, because the mean of its divisors is an integer number (2656220616).
Almost surely, 241121300432 is an apocalyptic number.
It is an amenable number.
41121300432 is an abundant number, since it is smaller than the sum of its proper divisors (65127524208).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
41121300432 is a wasteful number, since it uses less digits than its factorization.
41121300432 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 151611 (or 151605 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 41121300432 its reverse (23400312114), we get a palindrome (64521612546).
The spelling of 41121300432 in words is "forty-one billion, one hundred twenty-one million, three hundred thousand, four hundred thirty-two".
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