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41122200131953 is a prime number
BaseRepresentation
bin10010101100110100000100…
…01000011001100101110001
312101121020120211110022221121
421112122002020121211301
520342221231213210303
6223243140011422241
711442660311554033
oct1126320210314561
9171536524408847
1041122200131953
1112114910a14856
124741911754981
1319c3a647c7095
14a2247a13bc53
154b4a3967e9bd
hex256682219971

41122200131953 has 2 divisors, whose sum is σ = 41122200131954. Its totient is φ = 41122200131952.

The previous prime is 41122200131939. The next prime is 41122200132029. The reversal of 41122200131953 is 35913100222114.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 39592384893504 + 1529815238449 = 6292248^2 + 1236857^2 .

It is a cyclic number.

It is not a de Polignac number, because 41122200131953 - 237 = 40984761178481 is a prime.

It is a super-2 number, since 2×411222001319532 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (41122200131153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20561100065976 + 20561100065977.

It is an arithmetic number, because the mean of its divisors is an integer number (20561100065977).

Almost surely, 241122200131953 is an apocalyptic number.

It is an amenable number.

41122200131953 is a deficient number, since it is larger than the sum of its proper divisors (1).

41122200131953 is an equidigital number, since it uses as much as digits as its factorization.

41122200131953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12960, while the sum is 34.

The spelling of 41122200131953 in words is "forty-one trillion, one hundred twenty-two billion, two hundred million, one hundred thirty-one thousand, nine hundred fifty-three".