Base | Representation |
---|---|
bin | 10010101100110100010011… |
… | …01001011110000000100111 |
3 | 12101121020220121202100110212 |
4 | 21112122021221132000213 |
5 | 20342222011004210234 |
6 | 223243200314410035 |
7 | 11442663402511601 |
oct | 1126321151360047 |
9 | 171536817670425 |
10 | 41122326241319 |
11 | 12114976119674 |
12 | 4741947a3091b |
13 | 19c3a8497c9cb |
14 | a2248cba8171 |
15 | 4b4a457905ce |
hex | 256689a5e027 |
41122326241319 has 2 divisors, whose sum is σ = 41122326241320. Its totient is φ = 41122326241318.
The previous prime is 41122326241303. The next prime is 41122326241351. The reversal of 41122326241319 is 91314262322114.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 41122326241319 - 24 = 41122326241303 is a prime.
It is a super-2 number, since 2×411223262413192 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41122326241379) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20561163120659 + 20561163120660.
It is an arithmetic number, because the mean of its divisors is an integer number (20561163120660).
Almost surely, 241122326241319 is an apocalyptic number.
41122326241319 is a deficient number, since it is larger than the sum of its proper divisors (1).
41122326241319 is an equidigital number, since it uses as much as digits as its factorization.
41122326241319 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 124416, while the sum is 41.
The spelling of 41122326241319 in words is "forty-one trillion, one hundred twenty-two billion, three hundred twenty-six million, two hundred forty-one thousand, three hundred nineteen".
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