Base | Representation |
---|---|
bin | 111011110101110100101… |
… | …111111000110111001101 |
3 | 112120010102020121001122202 |
4 | 323311310233320313031 |
5 | 1014333333024204010 |
6 | 12425045454251245 |
7 | 603046125530606 |
oct | 73656457706715 |
9 | 15503366531582 |
10 | 4112242413005 |
11 | 1345aa06aa871 |
12 | 564b917b6b25 |
13 | 23aa23a56c2c |
14 | 103068280dad |
15 | 71e7ed9b6a5 |
hex | 3bd74bf8dcd |
4112242413005 has 16 divisors (see below), whose sum is σ = 4942737676800. Its totient is φ = 3284431607040.
The previous prime is 4112242412987. The next prime is 4112242413017. The reversal of 4112242413005 is 5003142422114.
It is a happy number.
4112242413005 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 4112242413005 - 28 = 4112242412749 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15111536 + ... + 15381254.
It is an arithmetic number, because the mean of its divisors is an integer number (308921104800).
Almost surely, 24112242413005 is an apocalyptic number.
It is an amenable number.
4112242413005 is a deficient number, since it is larger than the sum of its proper divisors (830495263795).
4112242413005 is a wasteful number, since it uses less digits than its factorization.
4112242413005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 274684.
The product of its (nonzero) digits is 7680, while the sum is 29.
Adding to 4112242413005 its reverse (5003142422114), we get a palindrome (9115384835119).
The spelling of 4112242413005 in words is "four trillion, one hundred twelve billion, two hundred forty-two million, four hundred thirteen thousand, five".
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