Base | Representation |
---|---|
bin | 1011111101111110011… |
… | …10010101111001101001 |
3 | 1110022110022222121121002 |
4 | 11332333032111321221 |
5 | 23214144401213342 |
6 | 512525544124345 |
7 | 41465444120354 |
oct | 5767716257151 |
9 | 1408408877532 |
10 | 411230101097 |
11 | 149446742592 |
12 | 678481666b5 |
13 | 2ca1812bc8a |
14 | 15c9184d29b |
15 | aa6c78ad32 |
hex | 5fbf395e69 |
411230101097 has 2 divisors, whose sum is σ = 411230101098. Its totient is φ = 411230101096.
The previous prime is 411230101091. The next prime is 411230101141. The reversal of 411230101097 is 790101032114.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 214439381776 + 196790719321 = 463076^2 + 443611^2 .
It is a cyclic number.
It is not a de Polignac number, because 411230101097 - 26 = 411230101033 is a prime.
It is a super-2 number, since 2×4112301010972 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (411230101091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205615050548 + 205615050549.
It is an arithmetic number, because the mean of its divisors is an integer number (205615050549).
Almost surely, 2411230101097 is an apocalyptic number.
It is an amenable number.
411230101097 is a deficient number, since it is larger than the sum of its proper divisors (1).
411230101097 is an equidigital number, since it uses as much as digits as its factorization.
411230101097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 29.
The spelling of 411230101097 in words is "four hundred eleven billion, two hundred thirty million, one hundred one thousand, ninety-seven".
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