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411230101141 is a prime number
BaseRepresentation
bin1011111101111110011…
…10010101111010010101
31110022110022222121122201
411332333032111322111
523214144401214031
6512525544124501
741465444120446
oct5767716257225
91408408877581
10411230101141
11149446742622
1267848166731
132ca1812bcc2
1415c9184d2cd
15aa6c78ad61
hex5fbf395e95

411230101141 has 2 divisors, whose sum is σ = 411230101142. Its totient is φ = 411230101140.

The previous prime is 411230101097. The next prime is 411230101151. The reversal of 411230101141 is 141101032114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 343479217041 + 67750884100 = 586071^2 + 260290^2 .

It is a cyclic number.

It is not a de Polignac number, because 411230101141 - 215 = 411230068373 is a prime.

It is a super-2 number, since 2×4112301011412 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (411230101151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205615050570 + 205615050571.

It is an arithmetic number, because the mean of its divisors is an integer number (205615050571).

Almost surely, 2411230101141 is an apocalyptic number.

It is an amenable number.

411230101141 is a deficient number, since it is larger than the sum of its proper divisors (1).

411230101141 is an equidigital number, since it uses as much as digits as its factorization.

411230101141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 411230101141 its reverse (141101032114), we get a palindrome (552331133255).

The spelling of 411230101141 in words is "four hundred eleven billion, two hundred thirty million, one hundred one thousand, one hundred forty-one".