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41123043132433 is a prime number
BaseRepresentation
bin10010101100110101101000…
…11000001100010000010001
312101121022202120201012012121
421112122310120030100101
520342224443020214213
6223243355404054241
711443020226133263
oct1126326430142021
9171538676635177
1041123043132433
1112115203855569
124741b07b34381
1319c3b6a354432
14a2251a09bb33
154b4a8869c88d
hex2566b460c411

41123043132433 has 2 divisors, whose sum is σ = 41123043132434. Its totient is φ = 41123043132432.

The previous prime is 41123043132397. The next prime is 41123043132463. The reversal of 41123043132433 is 33423134032114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 27420963669009 + 13702079463424 = 5236503^2 + 3701632^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-41123043132433 is a prime.

It is a super-2 number, since 2×411230431324332 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (41123043132463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20561521566216 + 20561521566217.

It is an arithmetic number, because the mean of its divisors is an integer number (20561521566217).

Almost surely, 241123043132433 is an apocalyptic number.

It is an amenable number.

41123043132433 is a deficient number, since it is larger than the sum of its proper divisors (1).

41123043132433 is an equidigital number, since it uses as much as digits as its factorization.

41123043132433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 62208, while the sum is 34.

Adding to 41123043132433 its reverse (33423134032114), we get a palindrome (74546177164547).

The spelling of 41123043132433 in words is "forty-one trillion, one hundred twenty-three billion, forty-three million, one hundred thirty-two thousand, four hundred thirty-three".