4112310043241 has 2 divisors, whose sum is σ = 4112310043242. Its totient is φ = 4112310043240.

The previous prime is 4112310043229. The next prime is 4112310043253. The reversal of 4112310043241 is 1423400132114.

It is a balanced prime because it is at equal distance from previous prime (4112310043229) and next prime (4112310043253).

It can be written as a sum of positive squares in only one way, i.e., 2400454435600 + 1711855607641 = 1549340^2 + 1308379^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4112310043241 is a prime.

It is a super-2 number, since 2×4112310043241² (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 4112310043241.

It is not a weakly prime, because it can be changed into another prime (4112310043291) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056155021620 + 2056155021621.

It is an arithmetic number, because the mean of its divisors is an integer number (2056155021621).

Almost surely, 2^{4112310043241} is an apocalyptic number.

It is an amenable number.

4112310043241 is a deficient number, since it is larger than the sum of its proper divisors (1).

4112310043241 is an equidigital number, since it uses as much as digits as its factorization.

4112310043241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 4112310043241 its reverse (1423400132114), we get a palindrome (5535710175355).

The spelling of 4112310043241 in words is "four trillion, one hundred twelve billion, three hundred ten million, forty-three thousand, two hundred forty-one".