Base | Representation |
---|---|
bin | 111011110101111001011… |
… | …101010100111001010001 |
3 | 112120010121202021200221111 |
4 | 323311321131110321101 |
5 | 1014334013241330134 |
6 | 12425101400053321 |
7 | 603051105303235 |
oct | 73657135247121 |
9 | 15503552250844 |
10 | 4112321433169 |
11 | 1346031271894 |
12 | 564bb4164241 |
13 | 23aa37233321 |
14 | 1030749705c5 |
15 | 71e86ca9c64 |
hex | 3bd79754e51 |
4112321433169 has 2 divisors, whose sum is σ = 4112321433170. Its totient is φ = 4112321433168.
The previous prime is 4112321433113. The next prime is 4112321433191. The reversal of 4112321433169 is 9613341232114.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2964894840769 + 1147426592400 = 1721887^2 + 1071180^2 .
It is a cyclic number.
It is not a de Polignac number, because 4112321433169 - 213 = 4112321424977 is a prime.
It is a super-2 number, since 2×41123214331692 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4112321433769) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056160716584 + 2056160716585.
It is an arithmetic number, because the mean of its divisors is an integer number (2056160716585).
Almost surely, 24112321433169 is an apocalyptic number.
It is an amenable number.
4112321433169 is a deficient number, since it is larger than the sum of its proper divisors (1).
4112321433169 is an equidigital number, since it uses as much as digits as its factorization.
4112321433169 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 93312, while the sum is 40.
The spelling of 4112321433169 in words is "four trillion, one hundred twelve billion, three hundred twenty-one million, four hundred thirty-three thousand, one hundred sixty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.063 sec. • engine limits •