41123403533 has 2 divisors, whose sum is σ = 41123403534. Its totient is φ = 41123403532.

The previous prime is 41123403491. The next prime is 41123403547. The reversal of 41123403533 is 33530432114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 32776205764 + 8347197769 = 181042^2 + 91363^2 .

It is a cyclic number.

It is not a de Polignac number, because 41123403533 - 2¹² = 41123399437 is a prime.

It is a super-2 number, since 2×41123403533² (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 41123403496 and 41123403505.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41123403583) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20561701766 + 20561701767.

It is an arithmetic number, because the mean of its divisors is an integer number (20561701767).

Almost surely, 2^41123403533 is an apocalyptic number.

It is an amenable number.

41123403533 is a deficient number, since it is larger than the sum of its proper divisors (1).

41123403533 is an equidigital number, since it uses as much as digits as its factorization.

41123403533 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12960, while the sum is 29.

Adding to 41123403533 its reverse (33530432114), we get a palindrome (74653835647).

The spelling of 41123403533 in words is "forty-one billion, one hundred twenty-three million, four hundred three thousand, five hundred thirty-three".