Base | Representation |
---|---|
bin | 10010101100110111101000… |
… | …01110110111110100101001 |
3 | 12101121102112020112210221102 |
4 | 21112123310032313310221 |
5 | 20342234141243300043 |
6 | 223244053553451145 |
7 | 11443055615050436 |
oct | 1126336416676451 |
9 | 171542466483842 |
10 | 41124114431273 |
11 | 12115703547205 |
12 | 4742166870ab5 |
13 | 19c3cab296383 |
14 | a225bc488b8d |
15 | 4b4aec7646b8 |
hex | 2566f43b7d29 |
41124114431273 has 2 divisors, whose sum is σ = 41124114431274. Its totient is φ = 41124114431272.
The previous prime is 41124114431261. The next prime is 41124114431321. The reversal of 41124114431273 is 37213441142114.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 40988843476009 + 135270955264 = 6402253^2 + 367792^2 .
It is a cyclic number.
It is not a de Polignac number, because 41124114431273 - 242 = 36726067920169 is a prime.
It is not a weakly prime, because it can be changed into another prime (41124114431473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20562057215636 + 20562057215637.
It is an arithmetic number, because the mean of its divisors is an integer number (20562057215637).
Almost surely, 241124114431273 is an apocalyptic number.
It is an amenable number.
41124114431273 is a deficient number, since it is larger than the sum of its proper divisors (1).
41124114431273 is an equidigital number, since it uses as much as digits as its factorization.
41124114431273 is an evil number, because the sum of its binary digits is even.
The product of its digits is 64512, while the sum is 38.
Adding to 41124114431273 its reverse (37213441142114), we get a palindrome (78337555573387).
The spelling of 41124114431273 in words is "forty-one trillion, one hundred twenty-four billion, one hundred fourteen million, four hundred thirty-one thousand, two hundred seventy-three".
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