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41124332020 = 2252056216601
BaseRepresentation
bin100110010011001100…
…111000000111110100
310221011000200112002011
4212103030320013310
51133210312111040
630520421054004
72654046024502
oct462314700764
9127130615064
1041124332020
1116493682362
127b78557304
133b54ca2395
141dc1a41672
15110a5773ea
hex9933381f4

41124332020 has 12 divisors (see below), whose sum is σ = 86361097284. Its totient is φ = 16449732800.

The previous prime is 41124332017. The next prime is 41124332057. The reversal of 41124332020 is 2023342114.

It can be written as a sum of positive squares in 2 ways, for example, as 12073174884 + 29051157136 = 109878^2 + 170444^2 .

It is a junction number, because it is equal to n+sod(n) for n = 41124331982 and 41124332000.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1028108281 + ... + 1028108320.

It is an arithmetic number, because the mean of its divisors is an integer number (7196758107).

Almost surely, 241124332020 is an apocalyptic number.

It is an amenable number.

41124332020 is an abundant number, since it is smaller than the sum of its proper divisors (45236765264).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

41124332020 is a wasteful number, since it uses less digits than its factorization.

41124332020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2056216610 (or 2056216608 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 41124332020 its reverse (2023342114), we get a palindrome (43147674134).

The spelling of 41124332020 in words is "forty-one billion, one hundred twenty-four million, three hundred thirty-two thousand, twenty".

Divisors: 1 2 4 5 10 20 2056216601 4112433202 8224866404 10281083005 20562166010 41124332020