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41124431443181 is a prime number
BaseRepresentation
bin10010101100111000001110…
…01000001011010011101101
312101121110100100001200112012
421112130013020023103231
520342240313422140211
6223244145240251005
711443066514442422
oct1126340710132355
9171543310050465
1041124431443181
111211585648aa19
124742234a70a65
1319c402bb6c498
14a2260c609d49
154b4b1a4d3d8b
hex25670720b4ed

41124431443181 has 2 divisors, whose sum is σ = 41124431443182. Its totient is φ = 41124431443180.

The previous prime is 41124431443169. The next prime is 41124431443213. The reversal of 41124431443181 is 18134413442114.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 39784240875625 + 1340190567556 = 6307475^2 + 1157666^2 .

It is a cyclic number.

It is not a de Polignac number, because 41124431443181 - 230 = 41123357701357 is a prime.

It is a super-2 number, since 2×411244314431812 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41124431443481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20562215721590 + 20562215721591.

It is an arithmetic number, because the mean of its divisors is an integer number (20562215721591).

Almost surely, 241124431443181 is an apocalyptic number.

It is an amenable number.

41124431443181 is a deficient number, since it is larger than the sum of its proper divisors (1).

41124431443181 is an equidigital number, since it uses as much as digits as its factorization.

41124431443181 is an evil number, because the sum of its binary digits is even.

The product of its digits is 147456, while the sum is 41.

Adding to 41124431443181 its reverse (18134413442114), we get a palindrome (59258844885295).

The spelling of 41124431443181 in words is "forty-one trillion, one hundred twenty-four billion, four hundred thirty-one million, four hundred forty-three thousand, one hundred eighty-one".