Base | Representation |
---|---|
bin | 1111010100100000… |
… | …1001010010100001 |
3 | 101121121111100022021 |
4 | 3311020021102201 |
5 | 31410303144441 |
6 | 1520030141441 |
7 | 203625060535 |
oct | 36510112241 |
9 | 11547440267 |
10 | 4112553121 |
11 | 182047a036 |
12 | 969351881 |
13 | 50703bbb1 |
14 | 2b0291bc5 |
15 | 1910a93d1 |
hex | f52094a1 |
4112553121 has 2 divisors, whose sum is σ = 4112553122. Its totient is φ = 4112553120.
The previous prime is 4112553061. The next prime is 4112553127. The reversal of 4112553121 is 1213552114.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2407276096 + 1705277025 = 49064^2 + 41295^2 .
It is a cyclic number.
It is not a de Polignac number, because 4112553121 - 213 = 4112544929 is a prime.
It is not a weakly prime, because it can be changed into another prime (4112553127) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056276560 + 2056276561.
It is an arithmetic number, because the mean of its divisors is an integer number (2056276561).
Almost surely, 24112553121 is an apocalyptic number.
It is an amenable number.
4112553121 is a deficient number, since it is larger than the sum of its proper divisors (1).
4112553121 is an equidigital number, since it uses as much as digits as its factorization.
4112553121 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1200, while the sum is 25.
The square root of 4112553121 is about 64129.1908650031. The cubic root of 4112553121 is about 1602.1524573280.
The spelling of 4112553121 in words is "four billion, one hundred twelve million, five hundred fifty-three thousand, one hundred twenty-one".
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