Base | Representation |
---|---|
bin | 10010101100111011011001… |
… | …01000101001010110100011 |
3 | 12101121121202000120120201122 |
4 | 21112131230220221112203 |
5 | 20342302310410004132 |
6 | 223245030233522455 |
7 | 11443156644003524 |
oct | 1126355450512643 |
9 | 171547660516648 |
10 | 41126134453667 |
11 | 1211654a8199aa |
12 | 474262b27342b |
13 | 19c42409310b3 |
14 | a2273087684b |
15 | 4b4bb9c7e912 |
hex | 25676ca295a3 |
41126134453667 has 2 divisors, whose sum is σ = 41126134453668. Its totient is φ = 41126134453666.
The previous prime is 41126134453633. The next prime is 41126134453687. The reversal of 41126134453667 is 76635443162114.
41126134453667 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 41126134453667 - 26 = 41126134453603 is a prime.
It is not a weakly prime, because it can be changed into another prime (41126134453687) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20563067226833 + 20563067226834.
It is an arithmetic number, because the mean of its divisors is an integer number (20563067226834).
Almost surely, 241126134453667 is an apocalyptic number.
41126134453667 is a deficient number, since it is larger than the sum of its proper divisors (1).
41126134453667 is an equidigital number, since it uses as much as digits as its factorization.
41126134453667 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 8709120, while the sum is 53.
The spelling of 41126134453667 in words is "forty-one trillion, one hundred twenty-six billion, one hundred thirty-four million, four hundred fifty-three thousand, six hundred sixty-seven".
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