Base | Representation |
---|---|
bin | 111011110110010101111… |
… | …100011001011010111010 |
3 | 112120011212001112220011120 |
4 | 323312111330121122322 |
5 | 1014341003112341333 |
6 | 12425221031210110 |
7 | 603066000403242 |
oct | 73662574313272 |
9 | 15504761486146 |
10 | 4112799340218 |
11 | 1346257009498 |
12 | 565108216936 |
13 | 23aab225146a |
14 | 1030bc214b22 |
15 | 71eb3c0bdb3 |
hex | 3bd95f196ba |
4112799340218 has 64 divisors (see below), whose sum is σ = 8883157248000. Its totient is φ = 1264791700224.
The previous prime is 4112799340217. The next prime is 4112799340231. The reversal of 4112799340218 is 8120439972114.
It is a super-2 number, since 2×41127993402182 (a number of 26 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (51).
It is not an unprimeable number, because it can be changed into a prime (4112799340217) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 715908 + ... + 2956031.
It is an arithmetic number, because the mean of its divisors is an integer number (138799332000).
Almost surely, 24112799340218 is an apocalyptic number.
4112799340218 is an abundant number, since it is smaller than the sum of its proper divisors (4770357907782).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
4112799340218 is a wasteful number, since it uses less digits than its factorization.
4112799340218 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3672179.
The product of its (nonzero) digits is 870912, while the sum is 51.
The spelling of 4112799340218 in words is "four trillion, one hundred twelve billion, seven hundred ninety-nine million, three hundred forty thousand, two hundred eighteen".
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