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4112933162557 is a prime number
BaseRepresentation
bin111011110110011101111…
…010111000111000111101
3112120012012101100202220111
4323312131322320320331
51014341241342200212
612425242211350021
7603102214023652
oct73663572707075
915505171322814
104112933162557
11134631560116a
12565144bb2311
1323ab03ba798b
141030d1ccbc29
1571ec0842ea7
hex3bd9deb8e3d

4112933162557 has 2 divisors, whose sum is σ = 4112933162558. Its totient is φ = 4112933162556.

The previous prime is 4112933162519. The next prime is 4112933162567. The reversal of 4112933162557 is 7552613392114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2820286955641 + 1292646206916 = 1679371^2 + 1136946^2 .

It is a cyclic number.

It is not a de Polignac number, because 4112933162557 - 211 = 4112933160509 is a prime.

It is a super-2 number, since 2×41129331625572 (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 4112933162557.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4112933162567) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056466581278 + 2056466581279.

It is an arithmetic number, because the mean of its divisors is an integer number (2056466581279).

Almost surely, 24112933162557 is an apocalyptic number.

It is an amenable number.

4112933162557 is a deficient number, since it is larger than the sum of its proper divisors (1).

4112933162557 is an equidigital number, since it uses as much as digits as its factorization.

4112933162557 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1360800, while the sum is 49.

The spelling of 4112933162557 in words is "four trillion, one hundred twelve billion, nine hundred thirty-three million, one hundred sixty-two thousand, five hundred fifty-seven".