Base | Representation |
---|---|
bin | 100110010011100010… |
… | …100010011011100101 |
3 | 10221011102101000021100 |
4 | 212103202202123211 |
5 | 1133213240312331 |
6 | 30521142510313 |
7 | 2654145214410 |
oct | 462342423345 |
9 | 127142330240 |
10 | 41130010341 |
11 | 16496900592 |
12 | 7b7a435399 |
13 | 3b5620cb34 |
14 | 1dc26bcb77 |
15 | 110ace9ae6 |
hex | 9938a26e5 |
41130010341 has 48 divisors (see below), whose sum is σ = 73420798464. Its totient is φ = 21649669632.
The previous prime is 41130010309. The next prime is 41130010379. The reversal of 41130010341 is 14301003114.
41130010341 is a `hidden beast` number, since 4 + 11 + 300 + 10 + 341 = 666.
It is not a de Polignac number, because 41130010341 - 25 = 41130010309 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (41130010301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 358210 + ... + 458883.
It is an arithmetic number, because the mean of its divisors is an integer number (1529599968).
Almost surely, 241130010341 is an apocalyptic number.
It is an amenable number.
41130010341 is a deficient number, since it is larger than the sum of its proper divisors (32290788123).
41130010341 is a wasteful number, since it uses less digits than its factorization.
41130010341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 817170 (or 817167 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 41130010341 its reverse (14301003114), we get a palindrome (55431013455).
The spelling of 41130010341 in words is "forty-one billion, one hundred thirty million, ten thousand, three hundred forty-one".
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