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41130013 is a prime number
BaseRepresentation
bin1001110011100…
…1100000011101
32212101121202211
42130321200131
541012130023
64025320421
71006412401
oct234714035
985347684
1041130013
1121242651
1211936111
1386a0cb2
145669101
153926a0d
hex273981d

41130013 has 2 divisors, whose sum is σ = 41130014. Its totient is φ = 41130012.

The previous prime is 41129993. The next prime is 41130073. The reversal of 41130013 is 31003114.

41130013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 27269284 + 13860729 = 5222^2 + 3723^2 .

It is a cyclic number.

It is not a de Polignac number, because 41130013 - 25 = 41129981 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 41129975 and 41130002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41130073) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20565006 + 20565007.

It is an arithmetic number, because the mean of its divisors is an integer number (20565007).

Almost surely, 241130013 is an apocalyptic number.

It is an amenable number.

41130013 is a deficient number, since it is larger than the sum of its proper divisors (1).

41130013 is an equidigital number, since it uses as much as digits as its factorization.

41130013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 41130013 is about 6413.2685114534. The cubic root of 41130013 is about 345.1858216211.

Adding to 41130013 its reverse (31003114), we get a palindrome (72133127).

The spelling of 41130013 in words is "forty-one million, one hundred thirty thousand, thirteen".