4113004013 has 2 divisors, whose sum is σ = 4113004014. Its totient is φ = 4113004012.

The previous prime is 4113003959. The next prime is 4113004039. The reversal of 4113004013 is 3104003114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2620108969 + 1492895044 = 51187^2 + 38638^2 .

It is a cyclic number.

It is not a de Polignac number, because 4113004013 - 2¹⁰ = 4113002989 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 4113003982 and 4113004000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4113004213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056502006 + 2056502007.

It is an arithmetic number, because the mean of its divisors is an integer number (2056502007).

Almost surely, 2^4113004013 is an apocalyptic number.

It is an amenable number.

4113004013 is a deficient number, since it is larger than the sum of its proper divisors (1).

4113004013 is an equidigital number, since it uses as much as digits as its factorization.

4113004013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 4113004013 is about 64132.7062659919. The cubic root of 4113004013 is about 1602.2110074391.

Adding to 4113004013 its reverse (3104003114), we get a palindrome (7217007127).

The spelling of 4113004013 in words is "four billion, one hundred thirteen million, four thousand, thirteen".