Base | Representation |
---|---|
bin | 10010101101000011001001… |
… | …11011011111011000010011 |
3 | 12101122000111100001112101022 |
4 | 21112201210323133120103 |
5 | 20342334323314034443 |
6 | 223250555443030055 |
7 | 11443365115533662 |
oct | 1126414473373023 |
9 | 171560440045338 |
10 | 41130300143123 |
11 | 12118298191064 |
12 | 47433b236b32b |
13 | 19c4755985ab9 |
14 | a22a07bdadd9 |
15 | 4b4d60832e68 |
hex | 256864edf613 |
41130300143123 has 2 divisors, whose sum is σ = 41130300143124. Its totient is φ = 41130300143122.
The previous prime is 41130300143117. The next prime is 41130300143129. The reversal of 41130300143123 is 32134100303114.
It is a balanced prime because it is at equal distance from previous prime (41130300143117) and next prime (41130300143129).
It is a cyclic number.
It is not a de Polignac number, because 41130300143123 - 218 = 41130299880979 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 41130300143092 and 41130300143101.
It is not a weakly prime, because it can be changed into another prime (41130300143129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20565150071561 + 20565150071562.
It is an arithmetic number, because the mean of its divisors is an integer number (20565150071562).
Almost surely, 241130300143123 is an apocalyptic number.
41130300143123 is a deficient number, since it is larger than the sum of its proper divisors (1).
41130300143123 is an equidigital number, since it uses as much as digits as its factorization.
41130300143123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 26.
Adding to 41130300143123 its reverse (32134100303114), we get a palindrome (73264400446237).
The spelling of 41130300143123 in words is "forty-one trillion, one hundred thirty billion, three hundred million, one hundred forty-three thousand, one hundred twenty-three".
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