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4113105013 is a prime number
BaseRepresentation
bin1111010100101001…
…0000000001110101
3101121122112101100201
43311022100001311
531410423330023
61520050040501
7203632546543
oct36512200165
911548471321
104113105013
111820816746
12969579131
135071a3164
142b0396d93
15191167bad
hexf5290075

4113105013 has 2 divisors, whose sum is σ = 4113105014. Its totient is φ = 4113105012.

The previous prime is 4113104981. The next prime is 4113105043. The reversal of 4113105013 is 3105013114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3709175409 + 403929604 = 60903^2 + 20098^2 .

It is a cyclic number.

It is not a de Polignac number, because 4113105013 - 25 = 4113104981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4113105043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056552506 + 2056552507.

It is an arithmetic number, because the mean of its divisors is an integer number (2056552507).

Almost surely, 24113105013 is an apocalyptic number.

It is an amenable number.

4113105013 is a deficient number, since it is larger than the sum of its proper divisors (1).

4113105013 is an equidigital number, since it uses as much as digits as its factorization.

4113105013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 180, while the sum is 19.

The square root of 4113105013 is about 64133.4936908945. The cubic root of 4113105013 is about 1602.2241221024.

Adding to 4113105013 its reverse (3105013114), we get a palindrome (7218118127).

The spelling of 4113105013 in words is "four billion, one hundred thirteen million, one hundred five thousand, thirteen".