4113140113132 has 24 divisors (see below), whose sum is σ = 7232338242752. Its totient is φ = 2046775683600.

The previous prime is 4113140113129. The next prime is 4113140113141. The reversal of 4113140113132 is 2313110413114.

It is a junction number, because it is equal to n+sod(n) for n = 4113140113097 and 4113140113106.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1322094 + ... + 3158197.

Almost surely, 2^{4113140113132} is an apocalyptic number.

It is an amenable number.

4113140113132 is a deficient number, since it is larger than the sum of its proper divisors (3119198129620).

4113140113132 is a wasteful number, since it uses less digits than its factorization.

4113140113132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4481389 (or 4481387 counting only the distinct ones).

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 4113140113132 its reverse (2313110413114), we get a palindrome (6426250526246).

The spelling of 4113140113132 in words is "four trillion, one hundred thirteen billion, one hundred forty million, one hundred thirteen thousand, one hundred thirty-two".