Base | Representation |
---|---|
bin | 111011110110101010111… |
… | …111000010110000001111 |
3 | 112120012202122210220212211 |
4 | 323312222333002300033 |
5 | 1014342214000332333 |
6 | 12425320041411251 |
7 | 603110515105663 |
oct | 73665277026017 |
9 | 15505678726784 |
10 | 4113152355343 |
11 | 1346418302a29 |
12 | 5651a6499b27 |
13 | 23ab3a421b55 |
14 | 1031130688a3 |
15 | 71ed4bddecd |
hex | 3bdaafc2c0f |
4113152355343 has 2 divisors, whose sum is σ = 4113152355344. Its totient is φ = 4113152355342.
The previous prime is 4113152355317. The next prime is 4113152355371. The reversal of 4113152355343 is 3435532513114.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4113152355343 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4113152355296 and 4113152355305.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4113152355443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056576177671 + 2056576177672.
It is an arithmetic number, because the mean of its divisors is an integer number (2056576177672).
Almost surely, 24113152355343 is an apocalyptic number.
4113152355343 is a deficient number, since it is larger than the sum of its proper divisors (1).
4113152355343 is an equidigital number, since it uses as much as digits as its factorization.
4113152355343 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 324000, while the sum is 40.
Adding to 4113152355343 its reverse (3435532513114), we get a palindrome (7548684868457).
The spelling of 4113152355343 in words is "four trillion, one hundred thirteen billion, one hundred fifty-two million, three hundred fifty-five thousand, three hundred forty-three".
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