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411321123331 is a prime number
BaseRepresentation
bin1011111110001001010…
…01100100001000000011
31110022200200021000121221
411333010221210020003
523214341201421311
6512542555055511
741500630601326
oct5770451441003
91408620230557
10411321123331
11149493061978
1267872741597
132ca30c4b2a1
1415c9d9847bd
15aa7576a671
hex5fc4a64203

411321123331 has 2 divisors, whose sum is σ = 411321123332. Its totient is φ = 411321123330.

The previous prime is 411321123307. The next prime is 411321123347. The reversal of 411321123331 is 133321123114.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-411321123331 is a prime.

It is a super-2 number, since 2×4113211233312 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 411321123296 and 411321123305.

It is not a weakly prime, because it can be changed into another prime (411321126331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205660561665 + 205660561666.

It is an arithmetic number, because the mean of its divisors is an integer number (205660561666).

Almost surely, 2411321123331 is an apocalyptic number.

411321123331 is a deficient number, since it is larger than the sum of its proper divisors (1).

411321123331 is an equidigital number, since it uses as much as digits as its factorization.

411321123331 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1296, while the sum is 25.

Adding to 411321123331 its reverse (133321123114), we get a palindrome (544642246445).

The spelling of 411321123331 in words is "four hundred eleven billion, three hundred twenty-one million, one hundred twenty-three thousand, three hundred thirty-one".