Base | Representation |
---|---|
bin | 1011111110001001010… |
… | …01100100001000000011 |
3 | 1110022200200021000121221 |
4 | 11333010221210020003 |
5 | 23214341201421311 |
6 | 512542555055511 |
7 | 41500630601326 |
oct | 5770451441003 |
9 | 1408620230557 |
10 | 411321123331 |
11 | 149493061978 |
12 | 67872741597 |
13 | 2ca30c4b2a1 |
14 | 15c9d9847bd |
15 | aa7576a671 |
hex | 5fc4a64203 |
411321123331 has 2 divisors, whose sum is σ = 411321123332. Its totient is φ = 411321123330.
The previous prime is 411321123307. The next prime is 411321123347. The reversal of 411321123331 is 133321123114.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-411321123331 is a prime.
It is a super-2 number, since 2×4113211233312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 411321123296 and 411321123305.
It is not a weakly prime, because it can be changed into another prime (411321126331) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205660561665 + 205660561666.
It is an arithmetic number, because the mean of its divisors is an integer number (205660561666).
Almost surely, 2411321123331 is an apocalyptic number.
411321123331 is a deficient number, since it is larger than the sum of its proper divisors (1).
411321123331 is an equidigital number, since it uses as much as digits as its factorization.
411321123331 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1296, while the sum is 25.
Adding to 411321123331 its reverse (133321123114), we get a palindrome (544642246445).
The spelling of 411321123331 in words is "four hundred eleven billion, three hundred twenty-one million, one hundred twenty-three thousand, three hundred thirty-one".
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