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41132153 is a prime number
BaseRepresentation
bin1001110011101…
…0000001111001
32212101201201002
42130322001321
541012212103
64025334345
71006421546
oct234720171
985351632
1041132153
1121244217
12119373b5
1386a1c6a
145669bcd
153927488
hex273a079

41132153 has 2 divisors, whose sum is σ = 41132154. Its totient is φ = 41132152.

The previous prime is 41132137. The next prime is 41132159. The reversal of 41132153 is 35123114.

41132153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 39904489 + 1227664 = 6317^2 + 1108^2 .

It is a cyclic number.

It is not a de Polignac number, because 41132153 - 24 = 41132137 is a prime.

It is a Chen prime.

It is a plaindrome in base 14.

It is not a weakly prime, because it can be changed into another prime (41132159) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20566076 + 20566077.

It is an arithmetic number, because the mean of its divisors is an integer number (20566077).

Almost surely, 241132153 is an apocalyptic number.

It is an amenable number.

41132153 is a deficient number, since it is larger than the sum of its proper divisors (1).

41132153 is an equidigital number, since it uses as much as digits as its factorization.

41132153 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 360, while the sum is 20.

The square root of 41132153 is about 6413.4353508864. The cubic root of 41132153 is about 345.1918082053.

Adding to 41132153 its reverse (35123114), we get a palindrome (76255267).

The spelling of 41132153 in words is "forty-one million, one hundred thirty-two thousand, one hundred fifty-three".