41132480941 has 2 divisors, whose sum is σ = 41132480942. Its totient is φ = 41132480940.

The previous prime is 41132480821. The next prime is 41132480953. The reversal of 41132480941 is 14908423114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 41116078441 + 16402500 = 202771^2 + 4050^2 .

It is a cyclic number.

It is not a de Polignac number, because 41132480941 - 2¹³ = 41132472749 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 41132480941.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41132480971) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20566240470 + 20566240471.

It is an arithmetic number, because the mean of its divisors is an integer number (20566240471).

Almost surely, 2^41132480941 is an apocalyptic number.

It is an amenable number.

41132480941 is a deficient number, since it is larger than the sum of its proper divisors (1).

41132480941 is an equidigital number, since it uses as much as digits as its factorization.

41132480941 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27648, while the sum is 37.

The spelling of 41132480941 in words is "forty-one billion, one hundred thirty-two million, four hundred eighty thousand, nine hundred forty-one".