Base | Representation |
---|---|
bin | 111011110110110101111… |
… | …010101100010010110011 |
3 | 112120020020102221001110111 |
4 | 323312311322230102303 |
5 | 1014343102423423042 |
6 | 12425350152442151 |
7 | 603115203052351 |
oct | 73666572542263 |
9 | 15506212831414 |
10 | 4113335764147 |
11 | 1346501893755 |
12 | 5652379a9357 |
13 | 23ab6941a47c |
14 | 10312d56c7d1 |
15 | 71ee5d6c517 |
hex | 3bdb5eac4b3 |
4113335764147 has 2 divisors, whose sum is σ = 4113335764148. Its totient is φ = 4113335764146.
The previous prime is 4113335764123. The next prime is 4113335764159. The reversal of 4113335764147 is 7414675333114.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4113335764147 - 223 = 4113327375539 is a prime.
It is a super-2 number, since 2×41133357641472 (a number of 26 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 4113335764147.
It is not a weakly prime, because it can be changed into another prime (4113339764147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056667882073 + 2056667882074.
It is an arithmetic number, because the mean of its divisors is an integer number (2056667882074).
Almost surely, 24113335764147 is an apocalyptic number.
4113335764147 is a deficient number, since it is larger than the sum of its proper divisors (1).
4113335764147 is an equidigital number, since it uses as much as digits as its factorization.
4113335764147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2540160, while the sum is 49.
The spelling of 4113335764147 in words is "four trillion, one hundred thirteen billion, three hundred thirty-five million, seven hundred sixty-four thousand, one hundred forty-seven".
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