Base | Representation |
---|---|
bin | 111011110110110101111… |
… | …010101100010010111111 |
3 | 112120020020102221001110221 |
4 | 323312311322230102333 |
5 | 1014343102423423114 |
6 | 12425350152442211 |
7 | 603115203052366 |
oct | 73666572542277 |
9 | 15506212831427 |
10 | 4113335764159 |
11 | 1346501893766 |
12 | 5652379a9367 |
13 | 23ab6941a48b |
14 | 10312d56c7dd |
15 | 71ee5d6c524 |
hex | 3bdb5eac4bf |
4113335764159 has 2 divisors, whose sum is σ = 4113335764160. Its totient is φ = 4113335764158.
The previous prime is 4113335764147. The next prime is 4113335764283. The reversal of 4113335764159 is 9514675333114.
4113335764159 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4113335764159 is a prime.
It is a super-2 number, since 2×41133357641592 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4113335768159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056667882079 + 2056667882080.
It is an arithmetic number, because the mean of its divisors is an integer number (2056667882080).
Almost surely, 24113335764159 is an apocalyptic number.
4113335764159 is a deficient number, since it is larger than the sum of its proper divisors (1).
4113335764159 is an equidigital number, since it uses as much as digits as its factorization.
4113335764159 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4082400, while the sum is 52.
The spelling of 4113335764159 in words is "four trillion, one hundred thirteen billion, three hundred thirty-five million, seven hundred sixty-four thousand, one hundred fifty-nine".
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