Base | Representation |
---|---|
bin | 1111010100101100… |
… | …1011111001011001 |
3 | 101121122222211201221 |
4 | 3311023023321121 |
5 | 31411004201413 |
6 | 1520055212041 |
7 | 203634620506 |
oct | 36513137131 |
9 | 11548884657 |
10 | 4113350233 |
11 | 1820973a03 |
12 | 969677021 |
13 | 50725a965 |
14 | 2b041c4ad |
15 | 1911b568d |
hex | f52cbe59 |
4113350233 has 2 divisors, whose sum is σ = 4113350234. Its totient is φ = 4113350232.
The previous prime is 4113350207. The next prime is 4113350237. The reversal of 4113350233 is 3320533114.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2977120969 + 1136229264 = 54563^2 + 33708^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4113350233 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4113350198 and 4113350207.
It is not a weakly prime, because it can be changed into another prime (4113350237) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056675116 + 2056675117.
It is an arithmetic number, because the mean of its divisors is an integer number (2056675117).
Almost surely, 24113350233 is an apocalyptic number.
It is an amenable number.
4113350233 is a deficient number, since it is larger than the sum of its proper divisors (1).
4113350233 is an equidigital number, since it uses as much as digits as its factorization.
4113350233 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3240, while the sum is 25.
The square root of 4113350233 is about 64135.4054559570. The cubic root of 4113350233 is about 1602.2559625724.
Adding to 4113350233 its reverse (3320533114), we get a palindrome (7433883347).
The spelling of 4113350233 in words is "four billion, one hundred thirteen million, three hundred fifty thousand, two hundred thirty-three".
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