Base | Representation |
---|---|
bin | 111011110110110111000… |
… | …001011100011001010101 |
3 | 112120020021201211100022100 |
4 | 323312313001130121111 |
5 | 1014343122200430003 |
6 | 12425352054152313 |
7 | 603115516520505 |
oct | 73666701343125 |
9 | 15506251740270 |
10 | 4113354311253 |
11 | 1346511301440 |
12 | 565242052699 |
13 | 23ab702124a5 |
14 | 103131bd9a05 |
15 | 71ee77d2ba3 |
hex | 3bdb705c655 |
4113354311253 has 48 divisors (see below), whose sum is σ = 6933674756736. Its totient is φ = 2322109624320.
The previous prime is 4113354311237. The next prime is 4113354311279. The reversal of 4113354311253 is 3521134533114.
4113354311253 is a `hidden beast` number, since 4 + 1 + 1 + 335 + 4 + 311 + 2 + 5 + 3 = 666.
It is not a de Polignac number, because 4113354311253 - 24 = 4113354311237 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4113354311453) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 12435001 + ... + 12761502.
It is an arithmetic number, because the mean of its divisors is an integer number (144451557432).
Almost surely, 24113354311253 is an apocalyptic number.
It is an amenable number.
4113354311253 is a deficient number, since it is larger than the sum of its proper divisors (2820320445483).
4113354311253 is a wasteful number, since it uses less digits than its factorization.
4113354311253 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25196634 (or 25196631 counting only the distinct ones).
The product of its digits is 64800, while the sum is 36.
Adding to 4113354311253 its reverse (3521134533114), we get a palindrome (7634488844367).
The spelling of 4113354311253 in words is "four trillion, one hundred thirteen billion, three hundred fifty-four million, three hundred eleven thousand, two hundred fifty-three".
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