Base | Representation |
---|---|
bin | 101110110000111001000111… |
… | …0110001111111001100101111 |
3 | 1222221102201110002012002211101 |
4 | 1131201302032301333030233 |
5 | 412403343311323403403 |
6 | 4014502553330103531 |
7 | 152433222512626054 |
oct | 13541621661771457 |
9 | 1887381402162741 |
10 | 411340003341103 |
11 | 10a07a352302091 |
12 | 3a174546a1aba7 |
13 | 1486a271452935 |
14 | 7380d68b1d02b |
15 | 3284d6dddd71d |
hex | 1761c8ec7f32f |
411340003341103 has 2 divisors, whose sum is σ = 411340003341104. Its totient is φ = 411340003341102.
The previous prime is 411340003341053. The next prime is 411340003341143. The reversal of 411340003341103 is 301143300043114.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 411340003341103 - 237 = 411202564387631 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (411340003341143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205670001670551 + 205670001670552.
It is an arithmetic number, because the mean of its divisors is an integer number (205670001670552).
Almost surely, 2411340003341103 is an apocalyptic number.
411340003341103 is a deficient number, since it is larger than the sum of its proper divisors (1).
411340003341103 is an equidigital number, since it uses as much as digits as its factorization.
411340003341103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 411340003341103 its reverse (301143300043114), we get a palindrome (712483303384217).
The spelling of 411340003341103 in words is "four hundred eleven trillion, three hundred forty billion, three million, three hundred forty-one thousand, one hundred three".
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