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41134312019 is a prime number
BaseRepresentation
bin100110010011110010…
…111100101001010011
310221011201110120001202
4212103302330221103
51133220340441034
630521415021415
72654226611633
oct462362745123
9127151416052
1041134312019
1116499279499
127b7b96a86b
133b57087ac8
141dc30bc6c3
15110b39947e
hex993cbca53

41134312019 has 2 divisors, whose sum is σ = 41134312020. Its totient is φ = 41134312018.

The previous prime is 41134312007. The next prime is 41134312033. The reversal of 41134312019 is 91021343114.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 41134312019 - 220 = 41133263443 is a prime.

It is a super-2 number, since 2×411343120192 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 41134311982 and 41134312000.

It is not a weakly prime, because it can be changed into another prime (41134312049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20567156009 + 20567156010.

It is an arithmetic number, because the mean of its divisors is an integer number (20567156010).

Almost surely, 241134312019 is an apocalyptic number.

41134312019 is a deficient number, since it is larger than the sum of its proper divisors (1).

41134312019 is an equidigital number, since it uses as much as digits as its factorization.

41134312019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 29.

The spelling of 41134312019 in words is "forty-one billion, one hundred thirty-four million, three hundred twelve thousand, nineteen".