Base | Representation |
---|---|
bin | 10010101101001110011000… |
… | …00011101001011101111100 |
3 | 12101122121001020110022201222 |
4 | 21112213030003221131330 |
5 | 20342434143234132030 |
6 | 223253433355052512 |
7 | 11444000326536155 |
oct | 1126471403513574 |
9 | 171577036408658 |
10 | 41136325302140 |
11 | 1211a8aa236222 |
12 | 47445b4141138 |
13 | 19c51a6020253 |
14 | a2301a0b892c |
15 | 4b50b478a3e5 |
hex | 2569cc0e977c |
41136325302140 has 48 divisors (see below), whose sum is σ = 86889421301760. Its totient is φ = 16358702592000.
The previous prime is 41136325302113. The next prime is 41136325302199. The reversal of 41136325302140 is 4120352363114.
It is a self number, because there is not a number n which added to its sum of digits gives 41136325302140.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 82795781 + ... + 83291139.
It is an arithmetic number, because the mean of its divisors is an integer number (1810196277120).
Almost surely, 241136325302140 is an apocalyptic number.
It is an amenable number.
41136325302140 is an abundant number, since it is smaller than the sum of its proper divisors (45753095999620).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
41136325302140 is a wasteful number, since it uses less digits than its factorization.
41136325302140 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 519542 (or 519540 counting only the distinct ones).
The product of its (nonzero) digits is 51840, while the sum is 35.
Adding to 41136325302140 its reverse (4120352363114), we get a palindrome (45256677665254).
The spelling of 41136325302140 in words is "forty-one trillion, one hundred thirty-six billion, three hundred twenty-five million, three hundred two thousand, one hundred forty".
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