Base | Representation |
---|---|
bin | 1011111110010010000… |
… | …01001001001001111101 |
3 | 1110022212210011112101211 |
4 | 11333021001021021331 |
5 | 23220013432210211 |
6 | 512554134004421 |
7 | 41502510546343 |
oct | 5771101111175 |
9 | 1408783145354 |
10 | 411394413181 |
11 | 14952046a6a4 |
12 | 678931a6711 |
13 | 2ca4319c36b |
14 | 15ca95c1993 |
15 | aa7bde5e21 |
hex | 5fc904927d |
411394413181 has 2 divisors, whose sum is σ = 411394413182. Its totient is φ = 411394413180.
The previous prime is 411394413113. The next prime is 411394413197. The reversal of 411394413181 is 181314493114.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 242547385081 + 168847028100 = 492491^2 + 410910^2 .
It is a cyclic number.
It is not a de Polignac number, because 411394413181 - 213 = 411394404989 is a prime.
It is a super-2 number, since 2×4113944131812 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (411394413581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205697206590 + 205697206591.
It is an arithmetic number, because the mean of its divisors is an integer number (205697206591).
Almost surely, 2411394413181 is an apocalyptic number.
It is an amenable number.
411394413181 is a deficient number, since it is larger than the sum of its proper divisors (1).
411394413181 is an equidigital number, since it uses as much as digits as its factorization.
411394413181 is an evil number, because the sum of its binary digits is even.
The product of its digits is 41472, while the sum is 40.
The spelling of 411394413181 in words is "four hundred eleven billion, three hundred ninety-four million, four hundred thirteen thousand, one hundred eighty-one".
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