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411394413181 is a prime number
BaseRepresentation
bin1011111110010010000…
…01001001001001111101
31110022212210011112101211
411333021001021021331
523220013432210211
6512554134004421
741502510546343
oct5771101111175
91408783145354
10411394413181
1114952046a6a4
12678931a6711
132ca4319c36b
1415ca95c1993
15aa7bde5e21
hex5fc904927d

411394413181 has 2 divisors, whose sum is σ = 411394413182. Its totient is φ = 411394413180.

The previous prime is 411394413113. The next prime is 411394413197. The reversal of 411394413181 is 181314493114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 242547385081 + 168847028100 = 492491^2 + 410910^2 .

It is a cyclic number.

It is not a de Polignac number, because 411394413181 - 213 = 411394404989 is a prime.

It is a super-2 number, since 2×4113944131812 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (411394413581) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205697206590 + 205697206591.

It is an arithmetic number, because the mean of its divisors is an integer number (205697206591).

Almost surely, 2411394413181 is an apocalyptic number.

It is an amenable number.

411394413181 is a deficient number, since it is larger than the sum of its proper divisors (1).

411394413181 is an equidigital number, since it uses as much as digits as its factorization.

411394413181 is an evil number, because the sum of its binary digits is even.

The product of its digits is 41472, while the sum is 40.

The spelling of 411394413181 in words is "four hundred eleven billion, three hundred ninety-four million, four hundred thirteen thousand, one hundred eighty-one".