Base | Representation |
---|---|
bin | 111011110111011111010… |
… | …111100101000000001111 |
3 | 112120022000220111222021211 |
4 | 323313133113211000033 |
5 | 1014401013441433234 |
6 | 12425543154235251 |
7 | 603141346144033 |
oct | 73673727450017 |
9 | 15508026458254 |
10 | 4114031202319 |
11 | 13468293a7745 |
12 | 5653b0885b27 |
13 | 23ac4a52034c |
14 | 103197a7a1c3 |
15 | 72036e3d164 |
hex | 3bddf5e500f |
4114031202319 has 2 divisors, whose sum is σ = 4114031202320. Its totient is φ = 4114031202318.
The previous prime is 4114031202269. The next prime is 4114031202373. The reversal of 4114031202319 is 9132021304114.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4114031202319 - 217 = 4114031071247 is a prime.
It is a super-2 number, since 2×41140312023192 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4114031202119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2057015601159 + 2057015601160.
It is an arithmetic number, because the mean of its divisors is an integer number (2057015601160).
Almost surely, 24114031202319 is an apocalyptic number.
4114031202319 is a deficient number, since it is larger than the sum of its proper divisors (1).
4114031202319 is an equidigital number, since it uses as much as digits as its factorization.
4114031202319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 31.
The spelling of 4114031202319 in words is "four trillion, one hundred fourteen billion, thirty-one million, two hundred two thousand, three hundred nineteen".
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