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411410245245253 is a prime number
BaseRepresentation
bin101110110001011001110100…
…1100001100101100101000101
31222221200102202100201112210221
41131202303221201211211011
5412411021140240322003
64014555131341544341
7152441260255151452
oct13542635141454505
91887612670645727
10411410245245253
1110a0a7117aa8341
123a18608a8750b1
1314873a86a36a27
14738450d904829
153286ad08847bd
hex1762ce9865945

411410245245253 has 2 divisors, whose sum is σ = 411410245245254. Its totient is φ = 411410245245252.

The previous prime is 411410245245191. The next prime is 411410245245271. The reversal of 411410245245253 is 352542542014114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 286585556030244 + 124824689215009 = 16928838^2 + 11172497^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-411410245245253 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (411410245245553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205705122622626 + 205705122622627.

It is an arithmetic number, because the mean of its divisors is an integer number (205705122622627).

Almost surely, 2411410245245253 is an apocalyptic number.

It is an amenable number.

411410245245253 is a deficient number, since it is larger than the sum of its proper divisors (1).

411410245245253 is an equidigital number, since it uses as much as digits as its factorization.

411410245245253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768000, while the sum is 43.

Adding to 411410245245253 its reverse (352542542014114), we get a palindrome (763952787259367).

The spelling of 411410245245253 in words is "four hundred eleven trillion, four hundred ten billion, two hundred forty-five million, two hundred forty-five thousand, two hundred fifty-three".