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411410425251223 is a prime number
BaseRepresentation
bin101110110001011001111010…
…0010000010000010110010111
31222221200110012220102210120201
41131202303310100100112113
5412411022022331014343
64014555201252041331
7152441264602163266
oct13542636420202627
91887613186383521
10411410425251223
1110a0a71aa674502
123a18611b003247
1314873ab5110538
1473845297a05dd
153286ae158e94d
hex1762cf4410597

411410425251223 has 2 divisors, whose sum is σ = 411410425251224. Its totient is φ = 411410425251222.

The previous prime is 411410425251211. The next prime is 411410425251251. The reversal of 411410425251223 is 322152524014114.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-411410425251223 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (411410425254223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205705212625611 + 205705212625612.

It is an arithmetic number, because the mean of its divisors is an integer number (205705212625612).

Almost surely, 2411410425251223 is an apocalyptic number.

411410425251223 is a deficient number, since it is larger than the sum of its proper divisors (1).

411410425251223 is an equidigital number, since it uses as much as digits as its factorization.

411410425251223 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 76800, while the sum is 37.

Adding to 411410425251223 its reverse (322152524014114), we get a palindrome (733562949265337).

The spelling of 411410425251223 in words is "four hundred eleven trillion, four hundred ten billion, four hundred twenty-five million, two hundred fifty-one thousand, two hundred twenty-three".