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41141104153 is a prime number
BaseRepresentation
bin100110010100001100…
…110110111000011001
310221012012020122010021
4212110030312320121
51133224110313103
630522220350441
72654341421032
oct462414667031
9127165218107
1041141104153
11164a2098526
127b820a5421
133b585c5516
141dc3d69a89
15110bc8bbbd
hex994336e19

41141104153 has 2 divisors, whose sum is σ = 41141104154. Its totient is φ = 41141104152.

The previous prime is 41141104097. The next prime is 41141104189. The reversal of 41141104153 is 35140114114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 25519104009 + 15622000144 = 159747^2 + 124988^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-41141104153 is a prime.

It is not a weakly prime, because it can be changed into another prime (41141104853) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20570552076 + 20570552077.

It is an arithmetic number, because the mean of its divisors is an integer number (20570552077).

Almost surely, 241141104153 is an apocalyptic number.

It is an amenable number.

41141104153 is a deficient number, since it is larger than the sum of its proper divisors (1).

41141104153 is an equidigital number, since it uses as much as digits as its factorization.

41141104153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 960, while the sum is 25.

Adding to 41141104153 its reverse (35140114114), we get a palindrome (76281218267).

The spelling of 41141104153 in words is "forty-one billion, one hundred forty-one million, one hundred four thousand, one hundred fifty-three".