411412311013351 has 2 divisors, whose sum is σ = 411412311013352. Its totient is φ = 411412311013350.

The previous prime is 411412311013273. The next prime is 411412311013391. The reversal of 411412311013351 is 153310113214114.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 411412311013351 - 2³⁹ = 410862555199463 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (411412311013391) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205706155506675 + 205706155506676.

It is an arithmetic number, because the mean of its divisors is an integer number (205706155506676).

Almost surely, 2^{411412311013351} is an apocalyptic number.

411412311013351 is a deficient number, since it is larger than the sum of its proper divisors (1).

411412311013351 is an equidigital number, since it uses as much as digits as its factorization.

411412311013351 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 31.

Adding to 411412311013351 its reverse (153310113214114), we get a palindrome (564722424227465).

The spelling of 411412311013351 in words is "four hundred eleven trillion, four hundred twelve billion, three hundred eleven million, thirteen thousand, three hundred fifty-one".