Base | Representation |
---|---|
bin | 10010101101010111100010… |
… | …00100010100010111001011 |
3 | 12101200001201211120220202201 |
4 | 21112223301010110113023 |
5 | 20343024230221431443 |
6 | 223300005243541031 |
7 | 11444233211153116 |
oct | 1126536104242713 |
9 | 171601654526681 |
10 | 41141241202123 |
11 | 121219a2121687 |
12 | 474554652a777 |
13 | 19c57aa6144ca |
14 | a23364d2757d |
15 | 4b52a112d34d |
hex | 256af11145cb |
41141241202123 has 2 divisors, whose sum is σ = 41141241202124. Its totient is φ = 41141241202122.
The previous prime is 41141241202121. The next prime is 41141241202153. The reversal of 41141241202123 is 32120214214114.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 41141241202123 - 21 = 41141241202121 is a prime.
Together with 41141241202121, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 41141241202091 and 41141241202100.
It is not a weakly prime, because it can be changed into another prime (41141241202121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20570620601061 + 20570620601062.
It is an arithmetic number, because the mean of its divisors is an integer number (20570620601062).
Almost surely, 241141241202123 is an apocalyptic number.
41141241202123 is a deficient number, since it is larger than the sum of its proper divisors (1).
41141241202123 is an equidigital number, since it uses as much as digits as its factorization.
41141241202123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3072, while the sum is 28.
Adding to 41141241202123 its reverse (32120214214114), we get a palindrome (73261455416237).
The spelling of 41141241202123 in words is "forty-one trillion, one hundred forty-one billion, two hundred forty-one million, two hundred two thousand, one hundred twenty-three".
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