41142120431 has 2 divisors, whose sum is σ = 41142120432. Its totient is φ = 41142120430.

The previous prime is 41142120413. The next prime is 41142120463. The reversal of 41142120431 is 13402124114.

Together with previous prime (41142120413) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-41142120431 is a prime.

It is a super-2 number, since 2×41142120431² (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 41142120397 and 41142120406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (41142120731) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20571060215 + 20571060216.

It is an arithmetic number, because the mean of its divisors is an integer number (20571060216).

Almost surely, 2^41142120431 is an apocalyptic number.

41142120431 is a deficient number, since it is larger than the sum of its proper divisors (1).

41142120431 is an equidigital number, since it uses as much as digits as its factorization.

41142120431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 41142120431 its reverse (13402124114), we get a palindrome (54544244545).

The spelling of 41142120431 in words is "forty-one billion, one hundred forty-two million, one hundred twenty thousand, four hundred thirty-one".