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4114221021997 is a prime number
BaseRepresentation
bin111011110111101010101…
…011101011101100101101
3112120022112010200210221021
4323313222223223230231
51014401411040200442
612430014054534141
7603146142451132
oct73675253535455
915508463623837
104114221021997
111346916567009
12565444367351
1323ac7a951998
141031b4d6c589
1572048935e67
hex3bdeaaebb2d

4114221021997 has 2 divisors, whose sum is σ = 4114221021998. Its totient is φ = 4114221021996.

The previous prime is 4114221021979. The next prime is 4114221022003. The reversal of 4114221021997 is 7991201224114.

Together with previous prime (4114221021979) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3995865069156 + 118355952841 = 1998966^2 + 344029^2 .

It is a cyclic number.

It is not a de Polignac number, because 4114221021997 - 235 = 4079861283629 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4114221021697) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2057110510998 + 2057110510999.

It is an arithmetic number, because the mean of its divisors is an integer number (2057110510999).

Almost surely, 24114221021997 is an apocalyptic number.

It is an amenable number.

4114221021997 is a deficient number, since it is larger than the sum of its proper divisors (1).

4114221021997 is an equidigital number, since it uses as much as digits as its factorization.

4114221021997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72576, while the sum is 43.

The spelling of 4114221021997 in words is "four trillion, one hundred fourteen billion, two hundred twenty-one million, twenty-one thousand, nine hundred ninety-seven".