Base | Representation |
---|---|
bin | 111011110111101011010… |
… | …101100110110011110101 |
3 | 112120022112220101011102012 |
4 | 323313223111212303311 |
5 | 1014401421343341041 |
6 | 12430015130254005 |
7 | 603146335043045 |
oct | 73675325466365 |
9 | 15508486334365 |
10 | 4114232012021 |
11 | 1346921792a7a |
12 | 565447b87305 |
13 | 23ac7cccc061 |
14 | 1031b65cd725 |
15 | 720498a73eb |
hex | 3bdeb566cf5 |
4114232012021 has 2 divisors, whose sum is σ = 4114232012022. Its totient is φ = 4114232012020.
The previous prime is 4114232012003. The next prime is 4114232012041. The reversal of 4114232012021 is 1202102324114.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3928664911396 + 185567100625 = 1982086^2 + 430775^2 .
It is a cyclic number.
It is not a de Polignac number, because 4114232012021 - 230 = 4113158270197 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4114232012041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2057116006010 + 2057116006011.
It is an arithmetic number, because the mean of its divisors is an integer number (2057116006011).
Almost surely, 24114232012021 is an apocalyptic number.
It is an amenable number.
4114232012021 is a deficient number, since it is larger than the sum of its proper divisors (1).
4114232012021 is an equidigital number, since it uses as much as digits as its factorization.
4114232012021 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 4114232012021 its reverse (1202102324114), we get a palindrome (5316334336135).
The spelling of 4114232012021 in words is "four trillion, one hundred fourteen billion, two hundred thirty-two million, twelve thousand, twenty-one".
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