4114232012113 has 2 divisors, whose sum is σ = 4114232012114. Its totient is φ = 4114232012112.

The previous prime is 4114232012089. The next prime is 4114232012159. The reversal of 4114232012113 is 3112102324114.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4112735328144 + 1496683969 = 2027988^2 + 38687^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4114232012113 is a prime.

It is not a weakly prime, because it can be changed into another prime (4114232016113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2057116006056 + 2057116006057.

It is an arithmetic number, because the mean of its divisors is an integer number (2057116006057).

Almost surely, 2^{4114232012113} is an apocalyptic number.

It is an amenable number.

4114232012113 is a deficient number, since it is larger than the sum of its proper divisors (1).

4114232012113 is an equidigital number, since it uses as much as digits as its factorization.

4114232012113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 4114232012113 its reverse (3112102324114), we get a palindrome (7226334336227).

The spelling of 4114232012113 in words is "four trillion, one hundred fourteen billion, two hundred thirty-two million, twelve thousand, one hundred thirteen".