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411425501 is a prime number
BaseRepresentation
bin11000100001011…
…101101011011101
31001200011120200112
4120201131223131
51320311104001
6104454135405
713124026154
oct3041355335
91050146615
10411425501
111a126a083
12b5951565
1367311c56
143c8da59b
15261bdcbb
hex1885dadd

411425501 has 2 divisors, whose sum is σ = 411425502. Its totient is φ = 411425500.

The previous prime is 411425473. The next prime is 411425507. The reversal of 411425501 is 105524114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 410103001 + 1322500 = 20251^2 + 1150^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-411425501 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (411425507) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205712750 + 205712751.

It is an arithmetic number, because the mean of its divisors is an integer number (205712751).

Almost surely, 2411425501 is an apocalyptic number.

It is an amenable number.

411425501 is a deficient number, since it is larger than the sum of its proper divisors (1).

411425501 is an equidigital number, since it uses as much as digits as its factorization.

411425501 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 800, while the sum is 23.

The square root of 411425501 is about 20283.6264262582. The cubic root of 411425501 is about 743.7558629013.

Adding to 411425501 its reverse (105524114), we get a palindrome (516949615).

The spelling of 411425501 in words is "four hundred eleven million, four hundred twenty-five thousand, five hundred one".