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4114301401241 is a prime number
BaseRepresentation
bin111011110111101111011…
…110010011100010011001
3112120022201201221111112022
4323313233132103202121
51014402042124314431
612430030045424225
7603151136614013
oct73675736234231
915508651844468
104114301401241
111346957977139
1256546726b075
1323ac914b5875
141031c18d31b3
1572050a1207b
hex3bdef793899

4114301401241 has 2 divisors, whose sum is σ = 4114301401242. Its totient is φ = 4114301401240.

The previous prime is 4114301401229. The next prime is 4114301401351. The reversal of 4114301401241 is 1421041034114.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3984974137600 + 129327263641 = 1996240^2 + 359621^2 .

It is a cyclic number.

It is not a de Polignac number, because 4114301401241 - 218 = 4114301139097 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 4114301401241.

It is not a weakly prime, because it can be changed into another prime (4114301407241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2057150700620 + 2057150700621.

It is an arithmetic number, because the mean of its divisors is an integer number (2057150700621).

Almost surely, 24114301401241 is an apocalyptic number.

It is an amenable number.

4114301401241 is a deficient number, since it is larger than the sum of its proper divisors (1).

4114301401241 is an equidigital number, since it uses as much as digits as its factorization.

4114301401241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 26.

Adding to 4114301401241 its reverse (1421041034114), we get a palindrome (5535342435355).

The spelling of 4114301401241 in words is "four trillion, one hundred fourteen billion, three hundred one million, four hundred one thousand, two hundred forty-one".