Base | Representation |
---|---|
bin | 10010101101011010110101… |
… | …10100011011011001000101 |
3 | 12101200020022111002121012211 |
4 | 21112231122310123121011 |
5 | 20343041343421442014 |
6 | 223300501303343421 |
7 | 11444325163604311 |
oct | 1126553264333105 |
9 | 171606274077184 |
10 | 41143015421509 |
11 | 121227226779a1 |
12 | 4745960751b71 |
13 | 19c5a01078c71 |
14 | a2349280cb41 |
15 | 4b5356c92cc4 |
hex | 256b5ad1b645 |
41143015421509 has 2 divisors, whose sum is σ = 41143015421510. Its totient is φ = 41143015421508.
The previous prime is 41143015421449. The next prime is 41143015421537. The reversal of 41143015421509 is 90512451034114.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 39150674702500 + 1992340719009 = 6257050^2 + 1411503^2 .
It is a cyclic number.
It is not a de Polignac number, because 41143015421509 - 211 = 41143015419461 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (41143015421539) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20571507710754 + 20571507710755.
It is an arithmetic number, because the mean of its divisors is an integer number (20571507710755).
Almost surely, 241143015421509 is an apocalyptic number.
It is an amenable number.
41143015421509 is a deficient number, since it is larger than the sum of its proper divisors (1).
41143015421509 is an equidigital number, since it uses as much as digits as its factorization.
41143015421509 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 40.
The spelling of 41143015421509 in words is "forty-one trillion, one hundred forty-three billion, fifteen million, four hundred twenty-one thousand, five hundred nine".
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